Keelon Russell Named Shaun Alexander Award Player of the Week
9/22/2026 9:00:00 AM | Football
The quarterback contributed 376 yards of offense and four touchdowns in 50-36 win over Florida State
TUSCALOOSA, Ala. – Alabama quarterback Keelon Russell was named the Shaun Alexander Award Player of the Week, the Maxwell Football Club announced Tuesday morning.
Shaun Alexander Award Player of the Week: Keelon Russell
- Accounted for 376 yards of offense and four touchdowns in 50-36 win against Florida State
- Went 23-of-30 for 320 yards and three touchdowns through the air
- Connected on scoring plays of 21, 46 and 16 yards, all in a matter of 2:36 before the halftime break
- Rushed three times for 56 yards, including a long scramble of 57 yards for a touchdown
Players Mentioned
QB
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